The bleachers at the football game are 7/8 full, and 1/2 the fans in the bleachers are rooting for the home team. What fraction of the bleachers are filled with the home team.

Answer: The fraction of the bleachers filled with the home team is [tex]\frac{7}{6}[/tex] Solution: Given that, The bleachers at the football game are [tex]\frac{7}{8}[/tex] In those bleachers [tex]\frac{1}{2}[/tex]  of the fans are rooting for the home team So, the fans that are filled with the home team is \left(\left(\frac{7}{8}\right) \times\left(\frac{1}{2}\right)\right) Hence, the required fraction is \left(\left(\frac{7}{8}\right) \times\left(\frac{1}{2}\right)\right) Removing the brackets we get, \frac{7 \times 1}{8 \times 2} =[tex]\frac{7}{6}[/tex]  The required fraction is [tex]\frac{7}{6}[/tex]