Troy bought a new boat that cost $28,000. The normal depreciation for such a boat is 14% per year. Which equation models the value of Troy's boat after t years? A) y = 28,0001.14t B) y = 28,0000.86t C) y = 28,000(1.14)t D) y = 28,000(0.86)t

Answer: Option D. [tex]y=28,000(0.86)^{t}[/tex]Step-by-step explanation:we know thatThe  formula to calculate the depreciated value  is equal to   [tex]y=P(1-r)^{x}[/tex]where  y is the depreciated value  P is the original value  r is the rate of depreciation  in decimal  x is Number of Time Periods  in this problem we have    [tex]P=\$28,000\\r=14\%=0.14\\x=t\ years[/tex]substitute [tex]y=28,000(1-0.14)^{t}[/tex] [tex]y=28,000(0.86)^{t}[/tex]