The point-slope form of the equation of the line that passes through (-4, -3) and (12,1) is y-1=1/4(×-12). What is the standard form of the equation for this line?

Answer:x - 4y = 8Step-by-step explanation:We are given point slope form of the equation of the line that passes through the point [tex](-4, -3)[/tex] and [tex](12,1)[/tex] which is [tex]y-1=\frac{1}{4} (x-12)[/tex].We are to write this equation in its standard form.From the given equation, we know that the slope is [tex]\frac{1}{4}[/tex] so we will find the y intercept.[tex]y=mx+c[/tex][tex]1=\frac{1}{4}\times (12) +c[/tex][tex]c=-2[/tex]Substituting the given values and the y intercept in the standard form of equation.[tex]y=mx+c[/tex][tex]y=\frac{1}{4} x-2[/tex]Rearranging this to get:x - 4y = 8